你好,台历制作方法很简单也,我教你个方法去有福网制作,下载有福艺术专家软件,是专门制作台历挂历的,
选择自己喜欢的台历模板,把你喜欢的照片拉到软件上就可以了。然后编辑一下就ok了。很好用哦~
谢谢!
你按照此步骤修复就好
首先打开“控制面板”-“添加/删除程序”,找到Office的程序,点击“更改”。
打开了Office的安装修复界面,选择第一个“添加或删除功能”,然后下一步;
一定要把“选择应用程序的高级自定义”勾选上,继续下一步;
在这里看到了程序组件列表,可以在这里选择任何组件的添加和卸载,这次要从“MicrosoftOfficeAess”中下手,点这一项前边的号,展开功能组件。
展开之后可以看到有个“日历控件”,前边显示×,表示该功能未使用,表示Word日历控件或Excel日历控件没有呢;点击“日历控件”前边的×,出现 *** 作方式,选择第一个“从本机运行”;点完之后就就发现前边的×没有了,并且还会自动开启一些关联“日历控件”的必须控件,不管他们,点更新。
到这里,稍等1min,就d出了成功更新的提示;回到Word发现插入对象里已经有“日历控件”的选项。
程序就是现实在计算机中的映像,如果你看一下现实中的台历,他有什么功能,你就该知道你的程序改怎样编程,实现什么功能了。把大问题化成小问题,把计算机要怎么做先想想成如果是个人他该怎么计算,如果你想明白了,接下来的只是用你的编程语言进行描述了。看好你哦。
此题不是很难,我会前三个
关键是算那一年的第一天是周几
给你个基本算法,一年是365天,闰年366天
364是7的倍数,这样一年多出一天,中间多少个闰年,在加上相应的天数即可
400年多出来的天数是400+97=497也是7的倍数,那么400年一轮回,这样就算400年以内的即可
一个子函数,返回这一年的第一天是周几,很好做
int ye(int year)
{
int y=year%400;
int day=y;
int i;
for(i=0;i<y;i++)
if(闰年判断)
day++;
return day%7;
}
做一个月份天数的全局数组
int mo[12]={31,28,31,30,31,30,31,31,30,31,30,31};
需要时用一个if判断闰年改变m0[1]的值是28还是29
打印子函数,有一个小技巧,就是每个月前面的空缺部分,这个1月份是ye子函数的返回值,后面的你看和前面月份是不是重合啊,吧这个记录下来在下一月份用即可
1 2
3 4
这样月份排列更好打印一些,你的那个截图有点麻烦
int pr(int year)
{
int k=ye(year);
int i,j,;
if(闰年判断)
mo[1]=29;
else
mo[1]=28;
for(i=0;i<12;i++)
{
printf("周几英文的打印");
for(j=0;j<k;j++)
printf("一般是四个空格,就是月份前面空缺的打印");
for(j=1;j<=mo[i];j++)
{
printf("%4d",j);
k++;
if((k+j)%7==0)
printf("\n");
}
k%=7;
if(k!=0)
printf("\n");
}
}
如果像你那样,感觉需要赋值一个大一点的数组,在吧数组打印出来更好,呵呵
设置日历的步骤:
工具/原料:华为mate30pro、HarmonyOS200、日历。
1、在手机界面点击日历选项。
2、点击界面三个点选项。
3、然后就可以看到设置选项,打开去设置。
4、进入设置里面然后选择去设置。
5、选择点击对应选项或者点击后面的开关去设置。
6、按照实际使用设置就好。
用输入第一天是星期几的,把这个程序改一下,不用输入月份,直接循环一下,从1-12就出来了,自己动手改下。
package comtest;
import javautilCalendar;
import javautilGregorianCalendar;
import javautilScanner;
public class test {
public static void main( String[] args ) {
String[] wd= { "日", "一", "二", "三", "四", "五", "六" };
/
Scanner s = new Scanner(Systemin);
P("请输入要查询的年份:");
int y = snextInt();
P("请输入月份:");
int m = snextInt();
if(y < 2000 || y > 2030) {
P("不在查询范围之内!");
return;
}
/
int y=2012;
int m=3;
GregorianCalendar g = new GregorianCalendar( y, m-1, 1 );
P( "\n星期\t" );
for ( int j = 0; j < wdlength; ++j ) P( wd[j] + "\t" );
P();
for ( int j = 0; j < gget( CalendarDAY_OF_WEEK ); ++j ) P( "\t" );
int thisMonth = gget( CalendarMONTH );
for ( int j = 1; j <= 31; ++j ) {
int d = gget( CalendarDAY_OF_MONTH );
P( d + "\t" );
if ( gget( CalendarDAY_OF_WEEK ) == 7 ) {
P("\n\t");
}
gadd( CalendarDAY_OF_YEAR, 1 );
if ( gget( CalendarMONDAY ) != thisMonth ) {
P("\n\n");
break;
}
}
}
static void P( String s )
{
Systemoutprint( s );
}
static void P()
{
Systemoutprintln();
}
}
//这是我曾经在网上看到一个兄弟写的,一个万年历系统。挺好的,你看看。
#ifndef _CALENDAR_H
#define _CALENDAR_H
#include <windowsh>
struct myDATE{
int year;
int month;
int day;
bool isRunYue;
};
class calendar{
public:
calendar(){};
~calendar(){};
LONG lDaysFrom1900(myDATE date);//date与1900年相差的天数
UINT lYearDays(UINT y);//农历y年的总天数
UINT leapDays(UINT y);//传回农历 y年闰月的天数
UINT leapMonth(UINT y);// 传回农历 y年闰哪个月 1-12 , 没闰传回 0
UINT monthDays(UINT y,UINT m);//传回农历 y年m月的总天数
myDATE Lunar(myDATE date);//输入阳历日期,返回阴历日期
char dayOfWeek(myDATE date);//输入阳历日期,返回星期几
char getLunarString (myDATE date );// 输入阴历日期,得到表示农历的字串
UINT solarDays(UINT y,UINT m);//传回国历 y年某m+1月的天数
private:
char m_slunar[100];//用于存储农历信息
static DWORD lunarInfo[];//
static UINT solarMonth[];
static char sSolarTerm[];
static DWORD dTermInfo[];
static char sFtv[];
};
#endif
#include "calendarh"
#include <stdioh>
DWORD calendar::lunarInfo[]={
0x04bd8,0x04ae0,0570,0x054d5,0x0d260,0x0d950,0x16554,0x056a0,0x09ad0,0x055d2,
0x04ae0,05b6,04d0,0x0d250,0x1d255,0x0b540,0x0d6a0,0da2,0x095b0,0x14977,
0x04970,04b0,0x0b4b5,0x06a50,0x06d40,0x1ab54,0x02b60,0x09570,0x052f2,0x04970,
0x06566,0x0d4a0,0x0ea50,0x06e95,0x05ad0,0x02b60,0x186e3,0x092e0,0x1c8d7,0x0c950,
0x0d4a0,0x1d8a6,0x0b550,0x056a0,0x1a5b4,0x025d0,0x092d0,0x0d2b2,0950,0x0b557,
0x06ca0,0x0b550,0x15355,0x04da0,05d0,0x14573,0x052d0,09a8,0x0e950,0x06aa0,
0ea6,0b50,0x04b60,0ae4,0570,0x05260,0x0f263,0x0d950,0x05b57,0x056a0,
0x096d0,0x04dd5,0x04ad0,04d0,0x0d4d4,0x0d250,0x0d558,0x0b540,0x0b5a0,0x195a6,
0x095b0,0x049b0,0974,04b0,0x0b27a,0x06a50,0x06d40,0f46,0b60,0x09570,
0x04af5,0x04970,0x064b0,0x074a3,0x0ea50,0x06b58,0x055c0,0b60,0x096d5,0x092e0,
0x0c960,0x0d954,0x0d4a0,0x0da50,0x07552,0x056a0,0bb7,0x025d0,0x092d0,0x0cab5,
0950,0x0b4a0,0x0baa4,0d50,0x055d9,0x04ba0,05b0,0x15176,0x052b0,0930,
0x07954,0x06aa0,0d50,0x05b52,0x04b60,06e6,04e0,0x0d260,0x0ea65,0x0d530,
0x05aa0,0x076a3,0x096d0,0x04bd7,0x04ad0,04d0,0x1d0b6,0x0d250,0x0d520,0x0dd45,
0x0b5a0,0x056d0,0x055b2,0x049b0,0577,04b0,0a50,0x1b255,0x06d20,0da0
};
UINT calendar::solarMonth[]={31,28,31,30,31,30,31,31,30,31,30,31};
UINT calendar::lYearDays(UINT y)
{
UINT i, sum = 348;
for(i=0x8000; i>0x8; i>>=1)
{
sum += (lunarInfo[y-1900] & i) 1: 0;
}
return(sum+leapDays(y));
}
UINT calendar::leapDays(UINT y)
{
if(leapMonth(y))
{
return (lunarInfo[y-1900] & 0x10000) 30: 29;
}
else
{
return 0;
}
}
UINT calendar::leapMonth(UINT y)
{
return lunarInfo[y-1900] & 0xf;
}
UINT calendar::monthDays(UINT y,UINT m)
{
return (lunarInfo[y-1900] & (0x10000>>m)) 30: 29;
}
LONG calendar::lDaysFrom1900(myDATE date)
{
LONG days;
days=365dateyear+(dateyear-1)/4-(dateyear-1)/100+(dateyear-1)/400-
(3651900+(1900-1)/4-(1900-1)/100+(1900-1)/400);
for(int i=0;i<datemonth-1;i++)
{
days+=solarMonth[i];
}
days+=dateday;
if((dateyear%4==0&&dateyear%100!=0)||dateyear%400==0)
{
if(datemonth>2)
{
days++;
}
}
return days;
}
myDATE calendar::Lunar(myDATE date)
{
LONG offset;
int i, leap=0, temp=0;
myDATE retdate;
offset=lDaysFrom1900(date)-30;
for(i=1900; i<2050 && offset>0; i++)
{
temp = lYearDays(i);
offset -= temp;
}
if(offset<0)
{
offset += temp;
i--;
}
retdateyear = i;
leap = leapMonth(i);
bool isLeap = false;
for(i=1; i<13 && offset>0; i++)
{
if(leap>0 && i==(leap+1) && isLeap==false)
{
--i;
isLeap = true;
temp = leapDays(retdateyear);
}
else
{
temp = monthDays(retdateyear, i);
}
if(isLeap==true && i==(leap+1))
{
isLeap = false;
}
offset -= temp;
}
if(offset==0 && leap>0 && i==leap+1)
{
if(isLeap)
{
isLeap = false;
}
else
{
isLeap = true;
--i;
}
}
if(offset<=0)
{
offset += temp;
--i;
}
retdatemonth = i;
retdateday = offset ;
retdateisRunYue=isLeap;
return retdate;
}
char calendar::getLunarString (myDATE date)
{
TCHAR szNongli[30], szNongliDay[10],szShuXiang[10];
const char cTianGan[] = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"}; /天干名称/
const char cDiZhi[] = {"子","丑","寅","卯","辰","巳","午", "未","申","酉","戌","亥"}; /地支名称/
const char cShuXiang[] = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"}; /属相名称/
const char cDayName[] = { "","初一","初二","初三","初四","初五", /农历日期名/
"初六","初七","初八","初九","初十",
"十一","十二","十三","十四","十五",
"十六","十七","十八","十九","二十",
"廿一","廿二","廿三","廿四","廿五",
"廿六","廿七","廿八","廿九","三十"};
const char cMonName[] = {"","正","二","三","四","五","六", "七","八","九","十","十一","腊"};
/--生成农历天干、地支、属相 ==> wNongli--/
int nShuXiang = ((dateyear - 4) % 60) % 12;
if ( nShuXiang < 0 || nShuXiang >= sizeof(cShuXiang)/sizeof(cShuXiang[0]) )
{
return NULL ;
}
wsprintf(szShuXiang,"%s",cShuXiang[nShuXiang]);
int nTianGan = ((dateyear - 4) % 60) % 10;
if ( nTianGan < 0 || nTianGan >= sizeof(cTianGan)/sizeof(cTianGan[0]) )
{
return NULL;
}
int nDiZhi = ((dateyear - 4) % 60) % 12;
if ( nDiZhi < 0 || nDiZhi >= sizeof(cDiZhi)/sizeof(cDiZhi[0]) )
{
return NULL;
}
wsprintf(szNongli,"%s(%s%s)年",szShuXiang,cTianGan[nTianGan],cDiZhi[nDiZhi]);
/--生成农历月、日 ==> wNongliDay--/
if ( datemonth < 0 || datemonth >= sizeof(cMonName)/sizeof(cMonName[0]) )
{
return NULL;
}
if (dateisRunYue)
{
wsprintf(szNongliDay,"闰%s",cMonName[datemonth]);
}
else
{
strcpy(szNongliDay,cMonName[datemonth]);
}
strcat(szNongliDay,"月");
if ( dateday < 0 || dateday >= sizeof(cDayName)/sizeof(cDayName[0]) )
{
return NULL;
}
strcat(szNongliDay,cDayName[dateday]);
strcat(szNongli,szNongliDay);
sprintf(m_slunar,szNongli);
return m_slunar;
}
char calendar::dayOfWeek(myDATE date)
{
char cWeekName[] = {"星期日","星期一","星期二","星期三","星期四","星期五","星期六"};
if(datemonth==1||datemonth==2)
{
datemonth+=12;
dateyear--;
}
return cWeekName[(dateday+1+2datemonth+3(datemonth+1)/5+dateyear+dateyear/4-dateyear/100+dateyear/400)%7];
}
UINT calendar::solarDays(UINT y,UINT m)
{
if(m==1)//2月
{
return(((y%4 == 0) && (y%100 != 0) || (y%400 == 0)) 29: 28);
}
else
{
return(solarMonth[m]);
}
}
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