使用成员函数作为线程人口函数现象观察

#include 
#include 
using namespace std;
class A {
public:
	A(int a) {
		std::cout << "构造函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
	A(const A& a) {
		std::cout << "拷贝构造函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
	~A() {
		std::cout << "析构函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
public:
	void run(int ab) {
		std::cout << ab << std::endl;
		std::cout << "子线程ID = " << std::this_thread::get_id() <执行的。并且复制的动作是在主线程当中执行的，而析构的动作是在子线程当中执行的。
 
如果传递的是&a我们再来看下现象如何：
 
#include 
#include 
using namespace std;
class A {
public:
	A(int a) {
		std::cout << "构造函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
	A(const A& a) {
		std::cout << "拷贝构造函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
	~A() {
		std::cout << "析构函数执行了" << "this = " << this << " threadid = " << std::this_thread::get_id() << std::endl;
	}
public:
	void run(int ab) {
		std::cout << ab << std::endl;
		std::cout << "子线程ID = " << std::this_thread::get_id() <
						
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原文地址: https://www.outofmemory.cn/zaji/5718418.html