P5728 【深基5.例5】旗鼓相当的对手 - 洛谷 | 计算机科学教育新生态 (luogu.com.cn)https://www.luogu.com.cn/problem/P5728
#include#include using namespace std; int main() { int ans[1010][3]{}, n, sum1 = 0, sum2 = 0, f = 0; cin >> n; for (int i = 0; i < n; i++) { for (int k = 0; k < 3; k++) { cin >> ans[i][k]; } } for (int i = 0; i < n; i++) { for (int g = i + 1; g < n; g++) { sum1 = 0; sum2 = 0; for (int k = 0; k < 3; k++) { if (fabs(ans[i][k] - ans[g][k]) <= 5) { sum1 += ans[i][k]; sum2 += ans[g][k]; } else break; if (k == 2 && fabs(sum1 - sum2) <= 10) f++; } } } cout << f; return 0; }
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for (int i = 0; i < n; i++) {
for (int g = i + 1; g < n; g++) {
一个元素和后面的每一个元素进行对比
修改:
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