int count = 0
for (int i = 1i <101i++) {
System.out.print(i+" ")
count = count +1
if (count%10==0){
count =0
System.out.println()
}
}
}
首先找到能满足题意的能被3和7整除的数,然后按下列条件输出:
代码如汪颤袜下:
public class F {public static void main(String[] args) {
int k = 0
int count = 0
for (int i = 0 i <= 1000 i++) {
if (((i % 3) != 0) || ((i % 7) != 0)) {
continue
}
k++
// 当满足题意k能被3和7整除
if (k % 10 == 0) {
// 一行输出小于10个时继续输出
System.out.println(i + " ")
} else {
// 当一行满足10个后换行输出
System.out.print(i + " "困激)
}
}
}
}
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