linux – 在字符串外面加上$字符的Bash echo

概述任何人都可以解释有什么区别 echo $"Starting $CMD" 和 echo "String $CMD" 他们似乎看起来一样. 查看bash手册页的QUOTING部分： Words of the form $'string' are treated specially. The word expands to string, with backslash- escaped characte 任何人都可以解释有什么区别

echo $"Starting $CMD"

和

echo "String $CMD"

他们似乎看起来一样.

解决方法 查看bash手册页的QUOTING部分：

Words of the form $'string' are treated specially. The word expands to
string,with backslash- escaped characters replaced as specifIEd by the
ANSI C standard. Backslash escape sequences,if present,are decoded as
follows:

\a alert (bell) \b backspace \e an escape character \f form Feed \n new line \r carriage return \t horizontal tab \v vertical tab \ backslash \’ single quote \nnn the eight-bit character whose value is the octal value nnn (one to three digits) \xHH the eight-bit character whose value is the hexadecimal value HH (one or two hex digits) \cx a control-x character

The expanded result is single-quoted,as if the dollar sign had not been present.

请注意以下说明双引号字符串前面带$($“string”)：

A double-quoted string preceded by a dollar sign ($) will cause the string to be translated according to the current locale. If the current locale is C or POSIX,the dollar sign is ignored. If the string is translated and replaced,the replacement is double-quoted.

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