ios – 检查字符串中是否包含表情符号

概述我得到一个字符串的文本大小 textSize = [[tempDict valueForKeyPath:@"caption.text"] sizeWithFont:[UIFont systemFontOfSize:12] constrainedToSize:CGSizeMake(280, CGFLOAT_MAX) lineBreakMode: NSLineBreakByWordWrapping]; 我得到一个字符串的文本大小

textSize = [[tempDict valueForKeyPath:@"caption.text"] sizeWithFont:[UIFont systemFontOfSize:12] constrainedToSize:CGSizeMake(280,CGfloat_MAX) lineBreakMode: NSlineBreakByWorDWrapPing];

我唯一的问题是,如果字符串只包含一个表情符号,我的应用程序崩溃.有没有一个简单的方法来检查emojis,或者我必须创建一个所有可能的emojis的数组,然后使用它来检查它们？

错误：

-[NSNull sizeWithFont:constrainedToSize:lineBreakMode:]: unrecognized selector sent to instance 0x3aa88a60if ([tempDict valueForKeyPath:@"caption.text"]){            NSLog(@"%@",[tempDict valueForKeyPath:@"caption"]);            //Measure the message label Box height            textSize = [[tempDict valueForKeyPath:@"caption.text"] sizeWithFont:[UIFont systemFontOfSize:12] constrainedToSize:CGSizeMake(280,CGfloat_MAX) lineBreakMode: NSlineBreakByWorDWrapPing];            int height = 320 + 20 + textSize.height;            [cellHeight addobject:[NSNumber numberWithInt:height]];}

解决方法 尝试这个代码：

- (BOol)stringContainsEmoji:(Nsstring *)string {    __block BOol returnValue = NO;    [string enumerateSubstringsInRange:NSMakeRange(0,[string length]) options:NsstringEnumerationByComposedCharacterSequences usingBlock:     ^(Nsstring *substring,NSRange substringRange,NSRange enclosingRange,BOol *stop) {         const unichar hs = [substring charac@R_419_6704@tIndex:0];         // surrogate pair         if (0xd800 <= hs && hs <= 0xdbff) {             if (substring.length > 1) {                 const unichar ls = [substring charac@R_419_6704@tIndex:1];                 const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;                 if (0x1d000 <= uc && uc <= 0x1f77f) {                     returnValue = YES;                 }             }         } else if (substring.length > 1) {             const unichar ls = [substring charac@R_419_6704@tIndex:1];             if (ls == 0x20e3) {                 returnValue = YES;             }         } else {             // non surrogate             if (0x2100 <= hs && hs <= 0x27ff) {                 returnValue = YES;             } else if (0x2B05 <= hs && hs <= 0x2b07) {                 returnValue = YES;             } else if (0x2934 <= hs && hs <= 0x2935) {                 returnValue = YES;             } else if (0x3297 <= hs && hs <= 0x3299) {                 returnValue = YES;             } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50) {                 returnValue = YES;             }         }     }];    return returnValue;}

总结

以上是内存溢出为你收集整理的ios – 检查字符串中是否包含表情符号全部内容，希望文章能够帮你解决ios – 检查字符串中是否包含表情符号所遇到的程序开发问题。

如果觉得内存溢出网站内容还不错，欢迎将内存溢出网站推荐给程序员好友。