linux – Bash脚本的工作原理是提示,但不是来自cron

概述从cron运行bash脚本时,它失败并出现以下错误 /bin/sh: -c: line 0: unexpected EOF while looking for matching ``'/bin/sh: -c: line 1: syntax error: unexpected end of file 奇怪的是,它在提示符下执行时效果很好 全剧本 #!/bin/shNOW=$(date +"%b- 从cron运行bash脚本时,它失败并出现以下错误

/bin/sh: -c: line 0: unexpected EOF while looking for matching ``'/bin/sh: -c: line 1: Syntax error: unexpected end of file

奇怪的是,它在提示符下执行时效果很好

全剧本

#!/bin/shNow=$(date +"%b-%d-%y")bu_PATH="/home/webserver/"curtime=$(date)echo ""echo "Starting backup: $curtime"echo ""echo "Moving to $bu_PATH"cd $bu_PATHBACKUP_file="backup_$Now.tgz"echo ""echo "The backup file will be called $BACKUP_file"RUN_BACKUP="/usr/local/psa/bin/pleskbackup --server --output-file=$bu_PATH$BACKUP_file"echo "Running backup...."echo `$RUN_BACKUP`curtime=$(date)echo "Backup complete: $curtime"echo ""echo "Remove older than 7 days of files..."ssh server '/shares/backup/webserver/cleanup.sh'curtime=$(date)echo ""echo "Connecting to FTP: $curtime"sftp -b server <<EOF        cd /shares/backup/webserver/        put $bu_PATH$BACKUP_file        quitEOF;curtime=$(date)echo "FTP Transfer Complete: $curtime"echo ""echo "Cleaning up Local backups"sh /home/cleanup.shecho ""echo "Clean up log files"find /home/webserver/logs/*.log -mtime +7 -exec rm {} \;echo "Job Complete"

这是crontab条目

/home/backup.sh > /home/webserver/logs/BackupLog-`date +%m%d%y`.log

谢谢
抢

解决方法 如果在crontab中使用反引号(`),则需要转义crontab条目中的％符号.

像这样：

/home/backup.sh > /home/webserver/logs/BackupLog-`date +\%m\%d\%y`.log

如果你不逃避它们,它们将被视为换行符.

总结

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