Suppose you have a random List of people standing in a queue. Each person is described by a pair of integers (h,k)
,where h
is the height of the person and k
is the number of people in front of this person who have a height greater than or equal to h
. Write an algorithm to reconstruct the queue.
Note:
The number of people is less than 1,100.
Example
input:[[7,0],[4,4],[7,1],[5,[6,2]]Output:[[5,2],1]]
假设有打乱顺序的一群人站成一个队列。 每个人由一个整数对(h,k)
表示,其中h
是这个人的身高,k
是排在这个人前面且身高大于或等于h
的人数。 编写一个算法来重建这个队列。
注意:
总人数少于1100人。
示例
输入:[[7,2]]输出:[[5,1]]
128ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 let ps = people.sorted { p1,p2 in 4 if p1[0] == p2[0] { return p1[1] < p2[1] } 5 return p1[0] > p2[0] 6 } 7 var result: [[Int]] = [] 8 for p in ps { 9 result.insert(p,at: p[1])10 }11 return result12 }13 }
136ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 guard !people.isEmpty else { return [] } 4 var sortedPeople = people.sorted { $0[0] == $1[0] ? $0[1] < $1[1] : $0[0] > $1[0] } 5 var curr = sortedPeople[0][0] 6 var bucket = [sortedPeople[0]] 7 var peopleHeightBuckets = [[[Int]]]() 8 for person in sortedPeople[1...] { 9 if person[0] == curr {10 bucket.append(person)11 } else {12 peopleHeightBuckets.append(bucket)13 curr = person[0]14 bucket = [person]15 }16 }17 peopleHeightBuckets.append(bucket)18 19 var queue = [[Int]]()20 queue.reserveCapacity(people.count)21 queue.append(contentsOf: peopleHeightBuckets[0])22 for bucket in peopleHeightBuckets[1...] {23 for person in bucket {24 queue.insert(person,at: min(person[1],queue.count))25 }26 }27 return queue28 }29 }
140ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 var people = people 4 people.sort(by:{(a:[Int],b:[Int]) in 5 return a[0] > b[0] || (a[0] == b[0] && a[1] < b[1])}) 6 for i in 0..<people.count 7 { 8 var p:[Int] = people[i] 9 if p[1] != i10 {11 people.remove(at:i)12 people.insert(p,at: p[1] )13 }14 }15 return people16 }17 }
160ms
1 class Solution {2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] {3 var res = [[Int]]()4 people.sorted(by: { ($0[0] == $1[0]) ? $0[1] < $1[1] : $0[0] > $1[0] }).forEach({res.insert($0,at: $0[1])})5 return res6 }7 }
168ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 let people = people.sorted { $0[0] == $1[0] ? $0[1] < $1[1] : $0[0] > $1[0] } 4 var result = [[Int]]() 5 6 for person in people { 7 result.insert(person,at: person[1]) 8 } 9 10 return result11 }12 }
368ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 let sorted = people.sorted { 4 if $0.first! == $1.first! { 5 return $0.last! < $1.last! 6 } else { 7 return $0.first! > $1.first! 8 } 9 }10 11 var res = [[Int]]()12 13 loop: for person in sorted {14 var num = 015 for i in 0..<res.count {16 if num == person.last! {17 res.insert(person,at: i)18 continue loop19 }20 num += 121 }22 23 res.append(person)24 }25 26 return res27 }28 }
1164ms
1 import Foundation 2 3 class Solution { 4 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 5 let sortedPairArray = people.sorted { (pair1,pair2) -> Bool in 6 var diff = pair1[0] - pair2[0] 7 if diff == 0 { 8 diff = pair1[1] - pair2[1] 9 }10 return diff < 011 }12 13 let peopleCount = people.count14 var outputArray = Array(repeating: [Int.max,0],count: peopleCount)15 for pair in sortedPairArray {16 let index = findindex(existingArray: outputArray,pair: pair)17 18 if index >= 0 {19 outputArray[index][0] = pair[0]20 outputArray[index][1] = pair[1]21 }22 }23 return outputArray24 }25 26 func findindex(existingArray: [[Int]],pair: [Int]) -> Int {27 let peopleCount = existingArray.count28 var count = 029 for i in 0..<peopleCount {30 if count == pair[1] {31 for j in i..<peopleCount {32 let existingPair = existingArray[i]33 if existingPair[0] == Int.max {34 return j35 }36 }37 }38 39 let existingPair = existingArray[i]40 if existingPair[0] >= pair[0] {41 count += 142 }43 }44 return -145 }46 }
2140ms
1 class Solution { 2 func reconstructQueue(_ people: [[Int]]) -> [[Int]] { 3 var res = [[Int]](repeating: [Int](),count: people.count) 4 var arr = people 5 arr.sort {$0.first! < $1.first!} 6 for item in arr { 7 let number = item.last! 8 let height = item.first! 9 var count = 010 for i in 0..<res.count {11 let slot = res[i]12 if slot.count == 0 || slot.first! >= height { 13 if count == number {14 res[i] = item15 }16 count += 117 }18 }19 }20 return res21 }22 }总结
以上是内存溢出为你收集整理的[Swift]LeetCode406. 根据身高重建队列 | Queue Reconstruction by Height全部内容,希望文章能够帮你解决[Swift]LeetCode406. 根据身高重建队列 | Queue Reconstruction by Height所遇到的程序开发问题。
如果觉得内存溢出网站内容还不错,欢迎将内存溢出网站推荐给程序员好友。
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)